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2 years ago

Answer choices 15.4 16 Please help

Mathematics

2 answers:

Ksivusya [100]2 years ago

5 0

Answer: 16 ft²

Step-by-step explanation:

use the following equation:

(1/2)bh

substitute in your values:

(1/2)(5)(6.4) = 16 ft²

BartSMP [9]2 years ago

5 0

16ft^2 that’s the correct answer

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25 POINTS!

steposvetlana [31]

$-\dfrac12x+3=-x+7$

Add -3 to both sides:

$-\dfrac12x+3-3=-x+7-3$
$-\dfrac12x=-x+4$

Multiply both sides by -2:

$-2\times\left(-\dfrac12\right)x=-2(-x+4)$
$x=-2(-x+4)$

On the right hand side, distribute the -2:

$x=2x-8$

Add -2x to both sides:

$x-2x=2x-2x-8$
$-x=-8$

Divide by -1:

$\dfrac{-x}{-1}=\dfrac{-8}{-1}$
$x=8$

(and not $x=-8$ , unless the original equation wasn't correctly written/interpreted?)

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2 years ago

Change 1 2/20 to a percent

True [87]

Answer:

110%

Step-by-step explanation:

1 2/20=22/20 which = 110%

8 0

2 years ago

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Write logbx + logby - logbz as a single logarithm.

IrinaK [193]

Logbx+logby-logbz
=logb(x*y)/z if b is the base of log.
There are two properties that you can apply to get the correct answer.
logb(x*y)=logbx+logby if b is the base of log.
logb(x/y)=logbx-logby if b is the base of log, so the correct answer for logbx+logby-logbz=logb(x*y)/z. Hope it help!

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2 years ago

4. A small high school holds its graduation ceremony in the gym. Because of seating constraints, students are limited to a maxim

Ad libitum [116K]

Answer:

(a) The mean and standard deviation of X is 2.6 and 1.2 respectively.

(b) The mean and standard deviation of T are 390 and 180 respectively.

(c) The distribution of T is N (390, 180²). The probability that all students’ requests can be accommodated is 0.7291.

Step-by-step explanation:

(a)

The random variable X is defined as the number of tickets requested by a randomly selected graduating student.

The probability distribution of the number of tickets wanted by the students for the graduation ceremony is as follows:

X P (X)

0 0.05

1 0.15

2 0.25

3 0.25

4 0.30

The formula to compute the mean is:

$\mu=\sum x\cdot P(X)$

Compute the mean number of tickets requested by a student as follows:

$\mu=\sum x\cdot P(X)\\=(0\times 0.05)+(1\times 0.15)+(2\times 0.25)+(3\times 0.25)+(4\times 0.30)\\=2.6$

The formula of standard deviation of the number of tickets requested by a student as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}\\=\sqrt{[(0^{2}\times 0.05)+(1^{2}\times 0.15)+(2^{2}\times 0.25)+(3^{2}\times 0.25)+(4^{2}\times 0.30)]-(2.6)^{2}}\\=\sqrt{1.44}\\=1.2$

Thus, the mean and standard deviation of X is 2.6 and 1.2 respectively.

(b)

The random variable T is defined as the total number of tickets requested by the 150 students graduating this year.

That is, T = 150 X

Compute the mean of T as follows:

$\mu=E(T)\\=E(150\cdot X)\\=150\times E(X)\\=150\times 2.6\\=390$

Compute the standard deviation of T as follows:

$\sigma=SD(T)\\=SD(150\cdot X)\\=\sqrt{V(150\cdot X)}\\=\sqrt{150^{2}}\times SD(X)\\=150\times 1.2\\=180$

Thus, the mean and standard deviation of T are 390 and 180 respectively.

(c)

The maximum number of seats at the gym is, 500.

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Here T = total number of seats requested.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{T}=n\times \mu_{X}=390$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{T}=n\times \sigma_{X}=180$

So, the distribution of T is N (390, 180²).

Compute the probability that all students’ requests can be accommodated, i.e. less than 500 seats were requested as follows:

$P(T$

Thus, the probability that all students’ requests can be accommodated is 0.7291.

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2 years ago

If each acute angle of a parallelogram measures 59 degrees, then what is the masure of each obtuse angle?

xenn [34]

A parallelogram has to have a total of 360 degrees in angles, so we take 59 x 2 to get 118, we then subtract 118 from 360, 360 - 118 = 242, we then divide by two because a parallelogram has 2 obtuse angles, giving us an answer of 121 degrees. Hope this helps

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3 years ago

Read 2 more answers