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2 years ago

What do we call the statement that determines if the null hypothesis is rejected?

Mathematics

2 answers:

Novay_Z [31]2 years ago

8 0

Answer:

An alternate hypothesis is a statement about a population parameter that is accepted when the null hypothesis is rejected. ... A test statistic is a value determined from sample information collected to test the null hypothesis

Step-by-step explanation:

geniusboy [140]2 years ago

3 0

Answer:

c) alternate hypothesis

Step-by-step explanation:

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Factor X^3-7x^2-5x+35 by grouping. What is the resulting expression

WARRIOR [948]

Answer:

(x-7) (x^2-5)

Step-by-step explanation:

x^3-7x^2-5x+35

Factor out an x^2 from the first two terms and -5 from the last 2 terms

x^2 (x-7) -5(x-7)

Factor out (x-7)

(x-7) (x^2-5)

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3 years ago

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The sum of two numbers is 82 and their difference is 26. find each of the numbers.

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54 because if x+y=82 and x-y=26 add 26 and 82 is 108 the divide it by 2 your answer is 54

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3 years ago

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Hunter-Best [27]

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3 years ago

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Name the ordered pairs for the vertices on the figure below

Elanso [62]

Answer:

where is the figure?

Step-by-step explanation:

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2 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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2 years ago

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