The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g
<h3>How to determine the number of half-lives </h3>
- Half-life (t½) = 30.5 s
- Time (t) = 41 s
- Number of half-lives (n) =?
n = t / t½
n = 41 / 30.5
n = 82/61
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 12 g
- Number of half-lives (n) = 82/61
N = N₀ / 2ⁿ
N = 12 / 2^(82/61)
N = 4.726 g
Learn more about half life:
brainly.com/question/26374513
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ax^2+bx+c=0
Step-by-step explanation:
hope this helps
Answer:
-0,1 > - 2/3
Step-by-step explanation:
-0,1 > - 2/3
Answer:
Step-by-step explanation:
21-6x=27-8x
Collecting like terms
8x - 6x = 27 - 21
2x = 6
x = 6/2
x = 3
