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olchik [2.2K]
3 years ago
14

Pls help .....................

Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

3rd answer

Step-by-step explanation:

Difficult to sxplain but basically all inequalities are correctly plotted on the graph.

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Please help :( really stuck on this and don’t understand please attempt to do it .
kenny6666 [7]
Answer) That graph is not a function
Explanation) The graph that you provided is not a function. It does not pass the vertical line test. The vertical line test is when you draw a vertical line (l) at any point on the graph and it should touch 1 or less parts of the graph. If you put the line at x=1, the vertical line only touches the graph at (1,8.5) but if you put the line at x=5, it touches (5,1) and (5,8.5) so it does not pass the test. You should be able to put the line anywhere and have it touch ONLY 1 point. There cannot be multiple of the same x values.
3 0
2 years ago
What is the center of the circle for this equation:<br> (x - 10)² + (y - 10)² = 25
Nastasia [14]

Answer:

Step-by-step explanation:

center: (-2,3)

Radius: 5

3 0
3 years ago
Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original pri
Tanzania [10]

Answer:

Amount of potteries sold at $9.50 is 30

And that of $6.50 is 65 potteries

Step-by-step explanation:

Kindly refer to the attached image for explanations

3 0
3 years ago
M/9+2/3=7/3<br><br> Solve for m.
Aleks04 [339]
<span>M/9+2/3=7/3
</span><span>M/9 =7/3 - 2/3
M/9 = 5/3
M = 5/3 x 9
M = 15</span>
3 0
3 years ago
Find the area. The figure is not drawn to scale.
VMariaS [17]

The figure on the top left is a triangle with base 11 and height 8, for an area of

A_1=\dfrac{11\cdot 8}{2}=44

Immediately below, we have a rectangle with dimensions 11 and 9, for an area of

A_2=11\cdot 9=99

Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height

A_3=11\cdot 9=99

Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of

A_4=\dfrac{8\cdot 9}{4}=36

Sum these areas and you'll get the total area

4 0
3 years ago
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