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levacccp [35]
3 years ago
5

I need help pls !!!!!!!

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

( 11/2, 5 ) !

Step-by-step explanation:

Refer to the picture!

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How do you solve this? (#11/#12)
zepelin [54]

\text{If}\ x_1,\ \text{and}\ x_2\ \text{are zeros of a polynomial function, then the function}\\\text{has equation}:\\\\f(x)=a(x-x_1)(x-x_2).\\----------------------------\\\\11.\ \text{We have the zeros}\ 3\ \text{and}\ i:\\\\f(x)=(x-3)(x-i)=(x)(x)+(x)(-i)+(-3)(x)+(-3)(-i)\\\\=x^2-xi-3x+3i=\boxed{x^2-(3+i)x+3i}\\\\12.\ \text{We have the zeros}\ -2\ \text{and}\ 2i:\\\\f(x)=(x-(-2))(x-2i)=(x+2)(x-2i)\\\\=x^2-(2i)^2=x^2-2^2i^2=x^2-4(-1)=\boxed{x^2+4}\\\\\text{used}\\\\(a-b)(a+b)=a^2-b^2\\\\i=\sqrt{-1}\to i^2=-1

3 0
3 years ago
Please I need help with this. Edward started his hike at an elevation of 115 feet below sea level. Throughout the hike he ascend
Marizza181 [45]
-115 + 3200 = 3085

3085 - 676 = 2409
4 0
3 years ago
Read 2 more answers
A series RLC circuit contains an inductor with a value of 200 millihenries and a capacitor with a value of 0.1 microfarad. What
vaieri [72.5K]

Answer:

  1125.4 Hz

Step-by-step explanation:

The resonant frequency is the frequency at with the inductive reactance is equal to the capacitive reactance. It is given by the relation ...

  f=\dfrac{1}{2\pi\sqrt{LC}}

where L is in henries, and C is in farads.

__

For the given circuit values, the resonant frequency is ...

  f=\dfrac{1}{2\pi\sqrt{0.2\cdot0.1\times10^{-6}}}\approx1125.4

The resonant frequency of this circuit is about 1125.4 hertz.

3 0
2 years ago
0.1 is rational because it can be written as?
Sladkaya [172]

Answer:

0.1 is rational as it can be written as \frac{1}{10}

Step-by-step explanation:

Rational decimals can be expressed as a fraction using integers, and 0.1 = \frac{1}{10}, so it is rational.

5 0
3 years ago
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Can someone help me with this please thank you
Dominik [7]

Answer:

1. 0.1

2. 0.01

I think it will help you.

6 0
2 years ago
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