1s -0
5s- 1
25s- 0
125s- 0
625s- 2
3125s- 0
15625s- 2
2020010. I think this is right but would like so confirmation, just taught myself this!
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer: 28 in.
Step-by-step explanation:
its simple
Answer:
9:15
Step-by-step explanation:

Answer:
x < 7
Step-by-step explanation:
the domain is the number range or interval of x the function is defined for to generate a y-value.
the graph shows that the y-values continue with x-values to the right up to but not including 7 (the empty dot says "excluding"). and with x- values to the left to negative infinity.
x=-1 is not a problem, because while for the left part of the function it is not included, but for the right part it is.
so, it is fully defined for all x < 7.