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almond37 [142]
3 years ago
9

Graph the line y-3 =4(x-5)

Mathematics
2 answers:
kap26 [50]3 years ago
5 0

Here is the graph :)

Ludmilka [50]3 years ago
4 0

you need to have the equation look like y=mx+b where m is a number that is your slope and b is another number that is your y-intercept.

I will do this now below:

y-3=4(x-5)

Factor 4 into (x-5) because you should always try to expand everything out as much as possible to be able to simplify things later:

y-3=4(x-5)\\y-3=4x-20

Now we should try to get y by itself since in y=mx+b format y is by itself.

y-3=4x-20\\\text{add three to both sides}\\y-3+3=4x-20+3\\y=4x-17

this is looking like point slope form now, compare the two below:

y=mx+b\\y=4x-17\\\text{ The m is represented by the 4, x is x, and -17 is the +b}\\

Now we need to graph our line. For this part we just pick some numbers for x and put it in the equation and solve for y. This will give us a list of x and y points.

y=4x-17

X\left[\begin{array}{ccc}x&y(x)&y\\1&4(1)-17&=-13\\2&4(2)-17&=-9\\3&4(3)-17&=-5\\4&4(4)-17&=-1\\5&4(5)-17&=3\end{array}\right]

So now we have some points and we can put them on a graph:

(1,-13)

(2,-9)

(3,-5)

(4,-1)

(5,3)

Ill attach a picture of the graph below.

And thats the answer, let me know if you have questions.


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For f(x+\frac{5}{4}), f(x) is translated \frac{5}{4} units left.

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The transformation of f(x)\rightarrow f(x+C) means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of f(x)\rightarrow f(x)+C means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0, so, the function translates left by \frac{5}{4} units.

Similarly, in the transformation of f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}, so, the function translates down by \frac{5}{4} units.

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