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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP PLEASE

Mathematics

2 answers:

Mars2501 [29]3 years ago

7 0

Answer:

19+19+10+10= 58 is the answer

irinina [24]3 years ago

4 0

19 + 10 + 19 + 10 = 58
If you see the lines on the other side clearly you will understand it

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A pair of sneakers was purchased. When they were purchased the price decreased by 20% for a sale price of $125.00. What was the

Oksana_A [137]

Answer:

%625

Step-by-step explanation:

to find the original price with the sale price and a decease percentage divide the original price of 125 by the decrease percentage of 20% or .2

8 0

3 years ago

8.5- __= 7.15 in words: 85 minus blank equals 7.15

Phoenix [80]

Answer:

Concept: Numerical Understanding

First off its eight point five minus blank equals seven point fifteen
The missing variable is a number that sums to 7.15
Instinctively you could rearrange or see the value missing is 1.35

3 0

3 years ago

Read 2 more answers

I need a lot of help from the smartest people now right now

Dominik [7]

Answer:

K) I, II, and III

Step-by-step explanation:

Given the quadratic equation in standard form, h = -at² + bt + c, where h is the height or the projectile of a baseball that changes over time, t. In the given quadratic equation, c represents the constant term. Altering the constant term, c, affects the h-intercept, the maximum value of h, and the t-intercept of the quadratic equation.

<h2>I. The h-intercept</h2>

The h-intercept is the value of the height, h, when t = 0. This means that setting t = 0 will leave you with the value of the constant term. In other words:

Set t = 0:

h = -at² + bt + c

h = -a(0)² + b(0) + c

h = -a(0) + 0 + c

h = 0 + c

h = c

Therefore, the value of the h-intercept is the value of c.

Hence, altering the value of c will also change the value of the h-intercept.

<h2>II. The maximum value of h</h2>

The maximum value of h occurs at the vertex, (t, h ). Changing the value of c affects the equation, especially the maximum value of h. To find the value of the t-coordinate of the vertex, use the following formula:

t = -b/2a

The value of the t-coordinate will then be substituted into the equation to find its corresponding h-coordinate. Thus, changing the value of c affects the corresponding h-coordinate of the vertex because you'll have to add the constant term into the rest of the terms within the equation. Therefore, altering the value of c affects the maximum value of h.

<h2>III. The t-intercept</h2>

The t-intercept is the point on the graph where it crosses the t-axis, and is also the value of t when h = 0. The t-intercept is the zero or the solution to the given equation. To find the t-intercept, set h = 0, and solve for the value of t. Solving for the value of t includes the addition of the constant term, c, with the rest of the terms in the equation. Therefore, altering the value of c also affects the t-intercept.

Therefore, the correct answer is Option K: I, II, and III.

5 0

3 years ago

Please do number 5(a and b)

NNADVOKAT [17]

Can you give me a better picture?

4 0

3 years ago

The American Community Survey showed that residents of New York City have the longest travel times to get to work compared to re

LiRa [457]

Answer:

The probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

Step-by-step explanation:

The random variable X can be defined as the travel times to get to work.

The expected travel time is, μ = 38.3 minutes.

The distribution of random variable X can be defined as the distribution of time interval between which a person reaches their work place at a constant average rate.

This implies that X follows an Exponential distribution with parameter, $\lambda=\frac{1}{\mu}=\frac{1}{38.3}$ .

The probability density function of X is:

$f_{X}(x)=\lambda e^{-\lambda x};\ x\geq 0$

Compute the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work as follows:

$P(17.24\leq X\leq 42.13)=\int\limits^{42.13}_{17.24}{\frac{1}{38.3} e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times \int\limits^{42.13}_{17.24}{ e^{-x/38.3}}}\, dx$

$=\frac{1}{38.3}\times| \frac{e^{-x/38.3}}{-1/38.3}}|^{42.13}_{17.24}\\$

$=-e^{42.13/38.3}+e^{17.34/38.3}\\=-0.3329+0.6375\\=0.3046$

Thus, the probability it will take a resident of the city between 17.24 and 42.13 minutes to travel to work is 0.3046.

6 0

3 years ago