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3 years ago

Find the slope of the line represented by the table of values

Mathematics

2 answers:

gtnhenbr [62]3 years ago

7 0

AnsweD

Step-by-step explanation:

Leya [2.2K]3 years ago

3 0

Answer:

-5/3

Step-by-step explanation:

To solve for slope we use the slope formula which is y2-y1/x2-x1.

For this problem I chose the points: (-5,10) and (-2,5)

-5 is x1, 10 is y1, -2 is x2 and 5 is y2

We now plug in the points into the slope formula:

5-10/-2-(-5)= -5/3

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I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)

Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5$

The interquartile range of the data is

$IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5$

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0

2 years ago

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

5 0

3 years ago

A line that is perpendicular to y=-4-10 passing through the point (8,11)

guapka [62]

Answer:

Step-by-step explanation:

11=4(8)+b

11=32+b

-21=b

y=4x-21

i think

4 0

2 years ago

Convert 153 degrees into radians to the nearest to decimals places

STatiana [176]

Since we know there are π radians in 180°, then how many radians are there in 153°?

$\bf \begin{array}{ccll}
radians&de grees\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\pi &180\\
x&153
\end{array}\implies \cfrac{\pi }{x}=\cfrac{180}{153}\implies \cfrac{\pi \cdot 153}{180}=x\implies \stackrel{simplified}{\cfrac{17\pi }{20}}=x$

6 0

3 years ago

What is 8 7/9 − 3 2/3 =

maks197457 [2]

[|] Answer [|]

$\boxed{5 \ 1/9}$

[|] Explanation [|]

Rewrite the equation with parts separated:

8 + 7/9 - 3 - 2/3

Solve the whole number parts:

8 - 3 = 5

Solve the fraction parts:

7/9 - 2/3

Find LCD of 7/9 & 2/3

7/9 - 6/9 = 1/9

5 + 1/9 = 5 1/9

$\boxed{[|] \ Eclipsed \ [|]}$

4 0

3 years ago