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Anuta_ua [19.1K]
2 years ago
11

how to write 2 to power of 11 multiplied 8 to power of 2 as single power of 2 . Working and explanation???

Mathematics
1 answer:
Umnica [9.8K]2 years ago
6 0
So the equation is ( the number in bracket are the power)=

2(11) *8(2)
So we can write 2(11) as 2*2*2*2*2*2*2*2*2*2*2*2 cos power 2(11) means 2 multiplied by 11 times 2
And for 8(2)
We will first split 8 as 2*2*2
Now we will multiply its power that is 2 times 8 *2*2*2[1st equation]
So 2 times 8=2*2*2*2*2*2[2nd equation]
Now multiply 1st and 2nd equation
=2*2*2*2*2*2*2*2*2
Now we write the complete equation of 2(11)*8(2)

2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2*2. Answerrr
So long omg
Ask me if u have any queries
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Consider the following frequency distribution.
Zarrin [17]

Answer:

Class interval                            10-19 20-29 30-39 40-49 50-59

cumulative frequency               10      24       41        48       50

cumulative relative frequency 0.2   0.48     0.82    0.96      1

Step-by-step explanation:

1.

We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.

Cumulative frequency

10

10+14=24

14+17=41

41+7=48

48+2=50

sum of frequencies is 50 so the relative frequency is f/50.

Relative frequency

10/50=0.2

14/50=0.28

17/50=0.34

7/50=0.14

2/50=0.04

Cumulative relative frequency

0.2

0.2+0.28=0.48

0.48+0.34=0.82

0.82+0.14=0.96

0.96+0.04=1

The cumulative relative frequency is calculated using relative frequency.

Relative frequency is calculated by dividing the respective frequency to the sum of frequency.

The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.

The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.

4 0
3 years ago
Leftmost digit of two numbers are 8 and 3 which is greater
anastassius [24]
8. 8 is greater than 3 and is all the way to theeft. if it was to the right, you'd need more info
6 0
3 years ago
Can u please answer this question
Paha777 [63]
One Way:
We can change the mixed number to a decimal for comparing.

1\frac{1}{4} m = \frac{5}{4} m = 1.25 m

1.4 m     >    1.25 m
Darren   >     Luke

Darren's jump was higher by (1.4-1.25) 0.15 m

Or another way change the decimal to a fraction and the mixed to an improper fraction too.

1\frac{1}{4} = \frac{5}{4} (Luke)
1.4 = \frac{7}{5}                               (Darren)
We need a common denominator to compare
\frac{5*5}{4*5}       (Luke)
\frac{7*4}{5*4}       (Darren)
\frac{25}{20}          (Luke)
\frac{28}{20}          (Darren)

\frac{28}{20}  >   \frac{25}{20}
        Darren           >            Luke
  
By:
\frac{28}{20} - \frac{25}{20} = \frac{3}{20}
Which is also by 0.15 m
Darren jumps higher and by 0.15 m
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3 years ago
What is the approximate circumference of the circle shown below?
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4 0
3 years ago
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Irina18 [472]

Answer:

A. add the areas of both bases to the rectangular area around the cylinder.

Step-by-step explanation:

If we flatten out the cylinder we would have two circles and a rectangle. When you roll up the rectangle, it would make the body of the cylinder. Surface area by definition the total area the surface of an object occupies.

So to get it, we add up the different shapes that make up the cylinder, which is the two circles and the rolled up rectangle.

7 0
3 years ago
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