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Contact [7]
3 years ago
14

The list below shows the ages of the first 20 fans to arrive at a professional basketball game. Display the fan age data on this

stem-and leaf plot.

Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0

I have no idea about the part A, but part b, all you have to do is get all the numbers of the fans, and put them in least to greatest. Then you count how fans are from 0-9, then you count how much fans are from 10 - 19, and so on. Im sorry that i couldn't answer it completely but i hope this helps.

Elena L [17]3 years ago
5 0

Answer:

Step-by-step explanation:

First we will arrange the ages of fans of the basketball game in the increasing order.

9, 11, 14, 14, 16, 25, 25, 27, 28 30, 33, 35, 35, 37, 38, 39, 42, 46, 47, 60

Part A. Now we will make stem-and-leaf plot

0  |  9

1   |  1, 4, 4, 6

2  |  5, 5, 7, 8

3  |  0, 3, 5, 5, 7, 8, 9

4  |  2, 6, 7

5  |

6  |  0

Part B.

Frequency table

Age           Number of Fans

0 - 9                  1

10 - 19               4

20 - 29             4

30 - 39             7

40 - 49             3

50 - 59             0

60 - 69             1

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Answer:

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Step-by-step explanation:

We want to to rewrite

1 - ( { 2 x - 1)}^{2}

Use difference of two squares to get:

{a}^{2}  -  {b}^{2}  = (a + b)(a - b)

This implies that:

{1}^{2} - ( { 2 x - 1)}^{2}  = (1 +( 2x - 1))(1  - (2x  - 1))

{1}^{2} - ( { 2 x - 1)}^{2}  = (1 + 2x - 1)(1  - 2x   + 1)

This finally simplifies to:

{1}^{2} - ( { 2 x - 1)}^{2}  =  2x (2  - 2x )

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In a class of 24 stundents 13 students sold over 150 raffle tickets each and the rest of the class sold about 60 raffle tickets
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4 0
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Last one anyone that can help me out?
Usimov [2.4K]

Answer:

Part a. t = 7.29 years.

Part b. t = 27.73 years.

Part c. p = $3894.00

Step-by-step explanation:

The formula for continuous compounding is: A = p*e^(rt); where A is the amount after compounding, p is the principle, e is the mathematical constant (2.718281), r is the rate of interest, and t is the time in years.

Part a. It is given that p = $2000, r = 2.5%, and A = $2400. In this part, t is unknown. Therefore: 2400 = 2000*e^(2.5t). This implies 1.2 = e^(0.025t). Taking natural logarithm on both sides yields ln(1.2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(1.2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(1.2)/0.025. This means that t = 7.29 years (rounded to the nearest 2 decimal places)!!!

Part b. It is given that p = $2000, r = 2.5%, and A = $4000. In this part, t is unknown. Therefore: 4000 = 2000*e^(2.5t). This implies 2 = e^(0.025t). Taking natural logarithm on both sides yields ln(2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(2)/0.025. This means that t = 27.73 years (rounded to the nearest 2 decimal places)!!!

Part c. It is given that A = $5000, r = 2.5%, and t = 10 years. In this part, p is unknown. Therefore 5000 = p*e^(0.025*10). This implies 5000 = p*e^(0.25). Making p the subject gives p = 5000/e^0.25. This means that p = $3894.00(rounded to the nearest 2 decimal places)!!!

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3 years ago
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