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Katena32 [7]
3 years ago
11

A 100 ft length of steel chain weighing 15 lb/ft is dangling from a pulley. How much work is required to wind the chain onto the

pulley?
Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
The correct answer is: A lot
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A box has 11 marbles, 3 of which are white and 8 of which are red. A sample of 4 marbles are selected randomly from the box with
aliina [53]

14/99

Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).

This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.

Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:

{(2×7)/(11×10×9)}×10=14/99

A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.

6 0
3 years ago
Need answer urgently.
Feliz [49]
Hey hey hey I see no picc
4 0
3 years ago
What is the % of 7/10
Delicious77 [7]

7/10=70/100=70%, so the answer is seventy-percent.

7 0
3 years ago
Read 2 more answers
Simplify. 54+4(3/4−1/2)2
Effectus [21]

Answer:

56

Step-by-step explanation:

54 + 4(3/4 − 1/2)2

=> 54 + 4(1/4)2

=> 54 + (1)2

=> 54 + 2

=> 56

Therefore, 56 is our answer.

Hoped this helped.

7 0
3 years ago
Suppose a subset of eight different days of the year is selected at random. What is the probability that each day is from a diff
goldfiish [28.3K]

Answer:

P = 0.05

Step-by-step explanation:

12 months * 30 days each = 360 days

From 306 days, we have to select 8 days = 360C8 ways(Total ways)

We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways

---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]

Therefore P = Number of ways of selecting each days from different month / Total number of ways

P = 12C8 * 30^8 / 360C8

P = 495 * 656100000000 / 6469697679132645

P = 0.0501985588982791

P = 0.05

Hence the probability that each day is from a different month is 0.05

6 0
3 years ago
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