Please help!!! 15 points!

Seth traveled 1 mile in 57.1 seconds. About how fast does Seth travel I. Miles per hour?

enyata [817]

57.1 seconds = 57.1 seconds * $\frac{1minute}{60seconds} * \frac{1hour}{60minutes}$ = 0.01057 hour
1 mile / 57.1 seconds = 1 mile / 0.01057 hour = 94.57 miles/hour

4 0

3 years ago

Why do you switch the inequality sign when multiplying or dividing by a negative?

Andreas93 [3]

If we multiply or divide both sides of an inequality by a negative number, you have to flip the inequality. Hope this helps :)

5 0

3 years ago

A 16 kg bag of watermelon for $8 per kg

Zarrin [17]

To solve this all we need to do is multiply.

Since 1 kg is for $8, then we will multiply to see how much 16 kg would be for.

16 × 8 = 128

So, 16 kg is for $128.

Hope I helped ya!!!!

8 0

3 years ago

In Problems 23–30, use the given zero to find the remaining zeros of each function

Talja [164]

Answer:

x = 2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

$f(x) = x^3 - 4x^2+ 4x - 16$

One of the zeroes of the above polynomial is 2i, that is :

$f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0$

Thus, we can write

$(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Now, we check if -2i is a root of the given polynomial:

$f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0$

Thus, we can write

$(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Therefore,

$(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Dividing the given polynomial:

$\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4$

Thus,

$(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

X = 4 is a root of the given polynomial.

$f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0$

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0

3 years ago

Can you help me plss!

Ksivusya [100]

(1/3) × the cone's volume = The cylinder's volume.

Step-by-step explanation:

Step 1:

The volume of any cone is obtained by multiplying $\frac{1}{3}$ with π, the square of the radius ( $r^{2}$ ) and the height ( $h$ ).

So the volume of the cone, $V=\pi r^{2} \frac{h}{3}$ .

Step 2:

The cylinder's volume is nearly the same as the cone but instead by multiplying $\frac{1}{3}$ we multiply with 1.

So the cylinder's volume is determined by multiplying π with the square of the radius of the cylinder ( $r^{2}$ ) and the height of the cylinder ( $h$ ).

So the the cone's volume, $V = \pi r^{2} h$ .

Step 3:

Now we equate both the volumes to each other.

The cone's volume : The cylinder's volume = $\pi r^{2} \frac{h}{3}: \pi r^{2} h$ = $\frac{1}{3} : 1$ .

So if we multiply the cone's volume with $\frac{1}{3}$ we will get the cylinder's volume with the same dimensions.

5 0

3 years ago