The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:
S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
Let Kamil get x. Therefore Sean would get (x + 56).
Kamil and Sean are in the ratio: 3:5
That means: x : (x + 56) = 3 : 5
x / (x + 56) = 3/5
5*x = 3*(x + 56)
5x = 3*x + 3*56
5x = 3x + 168
5x - 3x = 168
2x = 168
x = 168 / 2
x = 84
Therefore Kamil had, x = 84, and Sean had (x + 56) = 84 + 56 = 140
Kamil had $84 and Sean had $140
Answer:
(4, 3)
Step-by-step explanation:
Since, A (-4, 3) is reflected across the y-axis to obtain point B.
Therefore, y coordinate remains the same, x coordinate flips over the y axis to be positive.
(-4,3) ==>> (4,3)
Answer:
x=o and y= -6
Step-by-step explanation:
12-2x = - 2(y-x)
or,12-2x = -2y + 2x
or, 12 = - 2y + 4x
or, 12/2= 2x - y
or, 2x - y = 6
• 2x -6= y.....eqn_1
-2x=-2y+2x -12
or,4x +2y= -12
or,4x + 2(2x-6)= -12
or, 4x+4x-12=-12
or, 8x= 0
• x= o
putting the value of x in eqn...3
o=(y-0)+6
or, o= y + 6
•y = -6
Part A:
Look at the image attached to my answer for the graph of the inequalities.
There are two different lines provided, one with a more negative slope than the other. The shaded area between them represents the solution set.
The green line is 2x+y≤8, the blue line is x+y≥4
Part B:
To test if (8, 10) is included, substitute x = 8 and y = 10 into both inequalities. If it doesn't satisfy one of them, then it isn't included in the solution area.
2(8) + 10 ≤ 8
16 + 10 ≤ 8
26 ≤ 8... 26 is NOT less then or equal to 8
Thus, (8, 10) cannot be a solution since the inequality is not true.
Part C:
I'm going to choose a random point from the graph, (2, 3). For your answer, any point in the shaded region where both x and y is positive will work.
The point (2, 3) means that Sarah can buy 2 cupcakes and 3 pieces of fudge to get at least 4 pastries for her siblings while staying within her 8 dollar budget.
Let me know if you need any clarifications. Happy Studying~