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Nimfa-mama [501]
3 years ago
10

The table represents the height in meters of a baseball a pitcher threw to another player after a certain number of seconds. Wh

at are the missing values in the table?

Mathematics
2 answers:
emmainna [20.7K]3 years ago
6 0
A is 24.5
B is  0


The first 3 sec  are increasing.  On sec 4 it starts to decrease. .  
True [87]3 years ago
4 0

Answer:

A is 24.5

B is  0

Step-by-step explanation:

On edgenuity 2020

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joja [24]

Answer: x² + y² - 2x - 8y + 13 = 0

Step-by-step explanation:

the equation of the circle is in the form (x - a)² + (y - b)² = r²

where (a,b) is the center of the circle and r is the radius

      hence the equation is

                         (x - 1)² + (y - 4)² = 2²

                         x²-2x+1+y²-8y+16= 4

                         x²+ y² -2x- 8y + 17 =4

                         x² + y² - 2x - 8y = -13

                          x² + y² - 2x - 8y + 13 = 0

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3 years ago
Graphs of the following equations are straight lines except :
scoundrel [369]

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Step-by-step explanation:

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3 years ago
Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Round answers to three decimal places.
zlopas [31]

Answer:

a) x= arccos(3/5) = 0.927

Just one solution

b) cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c) x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d) x= -0.1145

Step-by-step explanation:

a. 5 cos(x) − 3 = 0

For this case we can do this:

5 cos(x) = 3

Now we can divide both sides by 5 and we got:

cos (x) = \frac{3}{5}

If we apply arccos on both sides we got:

x = arccos (\frac{3}{5})+2\pi n, x=2\pi-arccos (\frac{3}{5})+2\pi n

So for this case the possible solution is:

x= arccos(3/5) = 0.927

Just one solution. This is only the solution on the interval assumed.

b. 3 cos(x) + 5 = 0

We can do this:

3 cos (x) = -5

Then we can divide by 3 both sides and we got:

cos(x) = -\frac{5}{3}

But we know that the cosine can't be negative so then this equation no have solutions on the reals.

c. 3 sin(x) − 1 = 0

We can do this:

3 sin(x) = 1

Then we can divide both sides by 3 and we got:

sin(x) = \frac{1}{3}

The general solutions would be:

x = arcsin(\frac{1}{3}) + 2\pi n , x= \pi -arcsin (\frac{1}{3}) + 2\pi n

x = arcsin(\frac{1}{3})=0.3398

This is only the solution on the interval assumed.

d. tan(x) = −0.115

For this case we can solve the value of x like this:

x = arctan(-0.115) +\pi n

And then the only possible solution for this case is:

x= -0.1145

3 0
4 years ago
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