Hello,
f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280
f(n)=160*(-2)^(n-1)
4/11 = 0.36 (repeat: 36)
5/11 = 0.45 (repeat: 45)
6/11 = 0.54 (repeat: 54)
7/11 = 0.63 (repeat: 63)
The third fin is the answer.
Answer:
=−ax+x2−3a+3x
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hmmmmm you did not give the full equation for the original line.
However, parallel lines have identical slopes. Whatever coefficient (m) is associated with the x value, will be the slope of the parallel line when the equation is put in the form
y = mx + b