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3 years ago

Fifty students are going on a field trip. Twenty of the students are boys. What percent of the students are girls?

Mathematics

2 answers:

Vilka [71]3 years ago

8 0

Answer:

60% would be the correct answer

Step-by-step explanation:

svet-max [94.6K]3 years ago

4 0

Answer:

Step-by-step explanation:

If all in total there are fifty students and 20 of them are boys then there are 30 students that are girls

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A Number with a zero as an exponent is equal to 0

Sunny_sXe [5.5K]

Yes it is I learned this last year and your welcome

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2x^2+9x-35 factor or foil

notka56 [123]

You would need to facto 2x² + 9x - 35 to get (2x - 5)(x + 7).

We can find this first by dividing the 2x² into 2x and x, which we can put into the brackets:

(2x _ _)(x _ _)

Then we need to find two factors of -35 that have a difference of 9 when one is multiplied by 2, which gives us +7 and -5 as (7 × 2) - 5 = 14 - 5 = 9.

This gives our final answer as:

(2x - 5)(x + 7)

We cannot use foil on this expression as there are no brackets to expand.

I hope this helps!

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3 years ago

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If JK LM , which statement is true ?

siniylev [52]

The answer to this question would be: B. JK and LM meet at a right angle.

The reversed T symbol in this question means "perpendicular". That means the JK and LM line have 90-degree angle difference. A straight angle is 180 degree and right angle mean 90 degrees.
A perpendicular line should be in the same plane and intersect each other.

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3 years ago

The average length of a ladybug can range from 0.08 to 0.4 inches. find two lengths that are within the given span. write them a

inysia [295]

<u>Answer</u>

1) 11/100

2) 1/10

<u>Experience</u>

There are infinate fractions between any two integers. The same way there are somany numbers between 0.08 and 0.4.

Examples are 0.09, 0.10, 0.11. 0.12,0.2,0.3, 0.35 and many more.

I will just pick two of them and write them as a fraction.

1) 0.11 = 11/100

2) 0.20 = 20/200

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irinina [24]

For the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

<h3>Measures of a Data </h3>

From the question, we are to determine the minimum, lower quartile, median, upper quartile, maximum, and interquartile range of the given data set

The given data set is

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Minimum = 48

Lower quartile = (54+56)/2

Lower quartile = 110/2

Lower quartile = 55

Median = (63+64)/2

Median = 127/2

Median = 63.5

Upper quartile = (74+74)/2

Upper quartile = 148/2

Upper quartile = 74

Maximum = 80

Interquartile range = Upper quartile - Lower quartile

Interquartile range = 74 - 55

Interquartile range = 19

Hence, for the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

Learn more on Measures of a Data here: brainly.com/question/15097997

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