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Arisa [49]
3 years ago
7

Fifty students are going on a field trip. Twenty of the students are boys. What percent of the students are girls?

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

Answer:

60% would be the correct answer

Step-by-step explanation:

svet-max [94.6K]3 years ago
4 0

Answer:

30

Step-by-step explanation:

If all in total there are fifty students and 20 of them are boys then there are 30 students that are girls

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there is a 1 to 15 relationship  between miles and gallons

Step-by-step explanation:

6 0
3 years ago
Find the volume of the shape
jeka57 [31]

Answer:

i think. 8 times 12 = 96 times 20 = 1,920

7 0
3 years ago
The price of apples went down by $0.15 per pound. Kim bought 6 pounds of apples at the new price for a total of $8.88.
Tems11 [23]

Answer: (p x 6)+8.88= $9.78

Step-by-step explanation:

multiply 0.15 by 6

6 x 0.15= 0.90

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hope this helps! ;P

7 0
3 years ago
Which of the following equations will produce the graph shown below?
melisa1 [442]
The graph is a circle, centered at the origin, with radius=4.

We know that we can write the equation of a circle with radius r and center (a,b) as :

                      (x-a)^2+(y-b)^2=r^2.

Thus, substituting (a, b) with (0, 0) and r with 4, we have:

                      x^2+y^2=16.

The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

x^2+y^2=16\\\\x^2+y^2-16=0\\\\2(x^2+y^2-16)=0, 

we would still have the same roots.

Thus, the equation of the circle can be written as :

                                    2x^2+2y^2=32.


Answer: B

5 0
4 years ago
Read 2 more answers
A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5
Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element=\frac{1}{6}

We have to find that P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)

Total number of elements=6

C_1={1,2,3,4}

Number of elements in C_1=4

P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}

Using the formula

P(C_1)=\frac{4}{6}=\frac{2}{3}

C_2={3,4,5,6}

Number of elements in C_2=4

P(C_2)=\frac{4}{6}=\frac{2}{3}

C_1\cap C_2={3,4}

Number of elements in (C_1\cap C_2)=2

P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}

C_1\cup C_2={1,2,3,4,5,6}

P(C_1\cup C_2)=\frac{6}{6}=1

4 0
3 years ago
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