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2 years ago

14

Which describes a homogeneous mixture?

1 answer:

Lady_Fox [76]2 years ago

6 0

Answer:

A homogeneous mixture is a solid, liquid or gaseous mixture that has the same proportions of its components throughout any given sample. ... An example of a homogeneous mixture is air. In physical chemistry and materials science this refers to substances and mixtures which are in a single phase.

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Why does magnesium chloride have a much higher melting point than hydrogen chloride ?

pshichka [43]

Because chloride is more reactive than hydrogen.

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3 years ago

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What would be the pH of an H2SO4 solution if the [H+] = 4.58 x 10-5 moles/liter?

Ghella [55]

Answer: pH of an $H_2SO_4$ solution is 4.34

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

Putting in the values:

$pH=-\log[4.58\times 10^{-5}]$

$pH=4.34$

Thus pH of an $H_2SO_4$ solution if the $[H^+]$ is $4.58\times 10^{-5}]$ is 4.34

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2 years ago

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sleet_krkn [62]

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All compounds of carbon are made by <span>ionic bonding.

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3 years ago

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Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

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3 years ago

Which two equations represent double-replacement reactions?

enyata [817]

Answer: A and D, I believe

Explanation:

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2 years ago

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