Explanation:
When carbon atom tends to form single bonds then its hybridization is 
, when carbon atom tends to form double bond then its hybridization is 
and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
Answer:
The correct answer to the following question will be "Arrhenius base".
Explanation:
- An Arrhenius base seems to be a material that raises the ion concentration (hydroxide) when exposed to water and thereby reduces the concentration of ions (hydronium).
- This acid, as well as base model, claims an acid is indeed a material that incorporates hydrogen or ionizes protons throughout aqueous, while a base would be a material that comprises hydroxide while releases everything in a that solution
So that the above is the right answer.
Answer:
I think its B im not sure
but i hope this helps
Answer:
17.55 g of NaCl
Explanation:
The following data were obtained from the question:
Molarity = 3 M
Volume = 100.0 mL
Mass of NaCl =..?
Next, we shall convert 100.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100/1000
100 mL = 0.1 L
Therefore, 100 mL is equivalent to 0.1 L.
Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:
Molarity = 3 M
Volume = 0.1 L
Mole of NaCl =?
Molarity = mole /Volume
3 = mole of NaCl /0.1
Cross multiply
Mole of NaCl = 3 × 0.1
Mole of NaCl = 0.3 mole
Finally, we determine the mass of NaCl required to prepare the solution as follow:
Mole of NaCl = 0.3 mole
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl =?
Mole = mass /Molar mass
0.3 = mass of NaCl /58.5
Cross multiply
Mass of NaCl = 0.3 × 58.5
Mass of NaCl = 17.55 g
Therefore, 17.55 g of NaCl is needed to prepare the solution.
It's TISSUES.
CELLS, TISSUES, ORGANS, ORGAN SYSTEM, NEW ORGANISM
