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mixas84 [53]
3 years ago
11

The energy from nuclear fission is potentially limitless but production is restricted by the limited availability of

Chemistry
1 answer:
sineoko [7]3 years ago
6 0

Answer: uranium

Explanation: It’s hard to find when mining and is required for nuclear fission

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Identify the type of reaction described in the sentence below. then, write a chemical equation. be sure to specify the states of
natulia [17]

Answer : The type of reaction described in the sentence is Synthesis or Combination

Explanation :

The balanced equation for the reaction between Phosphorous and Oxygen gas can be written as

4P (s) + 5O_{2} (g) ------>  P_{4} O_{10}  (s)

From the above equation we can see that there are two different reactants ( P and O₂ ) which are combining with each other to give a single product.

This type of reaction is known as Combination or Synthesis.

A general form of Synthesis reaction is given below.

A + B ---->  AB

Here we can conclude that a synthesis / combination reaction is the one where 2 or more reactants combine together to give only one product .

6 0
3 years ago
12. help idk what to do at this point , I have notes and study till 3am , I still need help
GaryK [48]
I’m not good at this but I’m guessing it’ll be the first one!
5 0
3 years ago
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Which of the following molecules has a bent shape?
Yuri [45]
The answer is C good luck
4 0
3 years ago
The coefficients in a chemical equation??
cricket20 [7]
D is the answer I believe.
3 0
3 years ago
How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start
Nezavi [6.7K]

Answer:

18.7887 g of NaCl

Explanation:

<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>

Let us start by writing out the balanced equation of the reaction:

Na + Cl2 ---> NaCl2

1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.

mole = mass/molar mass

Therefore

18 g of Na = 18/23 = 0.7826 mole

23 g of Cl2 = 23/71 = 0.3239 mole

In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence

0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.

mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g

<u>Hence, 18.7887  grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>

3 0
3 years ago
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