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MArishka [77]
4 years ago
7

" title=" \frac{5}{12} \div \frac{2}{11} = " alt=" \frac{5}{12} \div \frac{2}{11} = " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
katrin2010 [14]4 years ago
7 0

Solve. To solve this equation, you must change the divide sign into a multiplication sign.

To do so, change it into a multiplication sign, and flip the second fraction

(5/12)/(2/11) = 5/12 x 11/2

Multiply across

5/12 x 11/2 = 55/24

55/24, or 4 7/12

hope this helps

<em>~Rise Above the Ordinary</em>

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0.04978706 rounded three decimal places
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4 years ago
Part B: The weatherman claimed that the temperature on Friday was the opposite of Thursday’s temperature. Which of the following
satela [25.4K]

Answer:

it will be d

Step-by-step explanation:

because I had a assignment over this and I put d and got it correct

7 0
3 years ago
What is 2and 2/3 divided by 4/5
Illusion [34]

Answer:

\frac{10}{3}  

I hope this helps!

5 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the
sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that \mu = 72.3, \sigma = 8

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

Z = \frac{X - \mu}{\sigma}

1.34 = \frac{X - 72.3}{8}

X - 72.3 = 1.34*8

X = 83

The minimum score required for an A grade is 83.

5 0
3 years ago
5. 3x-X-7=3 6.3x-3-X=3 7. -1 - 2x +3x=5 8. 3x - 22 - X=6 9. 2x+3x-10=10
Marta_Voda [28]
** 3x - x -7 = 3

2x = 10

x = 5

** <span>6. 3x - 3 -x = 3

18x - 3 - x = 3

17x = 6

x = </span>\frac{6}{17}

** <span>7. -1 - 2x + 3x = 5

-7 - 2x + 3x = 5

-7 + x = 5

x = 12

** </span><span>8. 3x - 22 - x = 6

24x - 22 - x = 6

23x = 28

x = </span>\frac{28}{23}

** <span>9. 2x + 3x -10 = 10

18x + 3x - 10 = 10

21x = 20

x = </span>\frac{20}{21}
6 0
4 years ago
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