Let x be the <span>length of each of two congruent sides.
</span>The triangle will be аcute if:
x² + x² > 8²
2x² > 64
x² > 32
x > √32
x > 5.657
So, the smallest possible length of one of two congruent sides have to be 5.7 cm (<span>to the nearest tenth)</span>
Answer:
5088
Step-by-step explanation:
212*24=5088
14. (n-5)*4+7
15. No, this would not be neccesary because if I were to distribute 1/2 to both 4 and 6, I know that I would get half of those numbers which would give me 2x+3. I also know that if I distribute 1/3 to both 9 and 24, I would get 1/3 of each number which would be 3 and 8.
Check the picture below.
so hmmm let's get the whole area of the rectangle, and then <u>get the areas of those 3 triangles and subtract their area from that of the rectangle's,</u> what's leftover is what we didn't subtract, namely, the white triangle.
