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Elenna [48]
3 years ago
13

in a poll 267 students voted. nominee c received 2/3 of the votes. how many votes did nominee c receive?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
4 0

Answer:

89

Step-by-step explanation:

2/3 times 267 is 178 after that you have to sub 178 from 267

balandron [24]3 years ago
3 0
Shiii ion kno man why my stuff gotta be 20 letters
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Two lines that have the same y intercept and different slopes intersect at exactly one point.
jek_recluse [69]

Answer:

False. They will be parallel to each other

6 0
3 years ago
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The recipe made eight servings but I only want to make a note for five people if the recipe for eight servings call for 2 cups o
Hunter-Best [27]
8 / 2 = 45 / x....8 servings to 2 cups = 45 servings to x cups
cross multiply
(8)(x) = (2)(45)
8x = 90
x = 90/8
x = 11 1/4 (or 11.25) cups of flour are needed <==
7 0
3 years ago
Can someone help me i cant understand with work
Masja [62]

Answer:

Right now it would be

-40

Since desend means down add -20 to -40

-40+(-20)=-60

         or

-40-20=-60

Then is goes up 35, which is positive

-60+35=-25

Therefore, the answer is -25

Hope this helps

Answer by

<em>Fishylikeswater</em>

<em></em>

3 0
3 years ago
Read 2 more answers
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num
AnnyKZ [126]

Answer:

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2            Combine like terms

2.80 = 0.35d + 2                       Subtract 2 from both sides

0.80 = 0.35d                             Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

5 0
2 years ago
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