Answer:
The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
Step-by-step explanation:
The ball will hit the ground when its height is equal to 0 meters, therefore using this value in the expression and solving for "t" will give us the correct solutions.

The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
The degree of the polynomial is 2.
to find the degree, put the polynomial in descending order with the highest exponents in front. the highest exponent is the degree.
3x^6 - 4 (highest exponent here is 6, degree would be 6)
Answer:
$38.26
Step-by-step explanation:
add the amounts together and multiply by 0.075 and 0.15 add these answers to the original amount
H= .6.5
V=<span>πr^2h
h= v/</span>πr^2 = 2940.5/<span>π*12^2 = 6.49993 = 6.5</span>