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2 years ago

2(r–2)≥8 jdjdhjdhjhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Mathematics

1 answer:

Delicious77 [7]2 years ago

5 0

Step-by-step explanation:

(r-2)

$\geqslant$

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A unit vector lies in the xy plane, at an angle of 137 degrees from the x axis, with a positive y component. What is the unit ve

Fed [463]

Answer: ( -0.731, 0.682)

Step-by-step explanation:

The unit vector is defined as a vector that points in the same direction as our vector (137 degrees from the x-axis) and has a magnitude of 1.

Knowing the angle, is really simple to do it.

First, we know that for a radius R and an angle A, the rectangular coordinates can be written as:

x = R*cos(A)

y = R*sin(A)

And if we want that the magnitude/modulus of our vector to be 1, then R = 1, and we know that A = 137°

x = 1*cos(137°) = -0.731

y = 1*sin(137°) = 0.682

Then the unit vector is: ( -0.731, 0.682)

8 0

2 years ago

Can anyone help please? No links cause I can’t see them.

tamaranim1 [39]

Answer:

Step-by-step explanation:

you have a right triangle with the hypotenuse of 41 and another side of 40

a= $\sqrt{41^2-40^2}$ = $\sqrt{1681-1600}$ = $\sqrt{81}$

a=9

5 0

2 years ago

In Kim’s homeroom, 4 students have no siblings, 9 students have

Papessa [141]

(9+8+2)/(4+9+8+2)=19/23=82%
Therefore very likely

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2 years ago

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A 6am one morning the temperature was -14 degrees by noon it rose 8 degrees and then rose another 2 degrees by 3pm. By 6pm the t

valentina_108 [34]

Answer:

-9 degrees

Step-by-step explanation:

-14 + 8 = -6

-6 + 2 = -4

-4 - 5 = -9

3 0

2 years ago

The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is

S_A_V [24]

Answer:

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

$V'=\frac{4}{3} \pi \cdot 3r^2r'$

I had to use constant multiple rule and chain rule.

We are given $V'=+25 \frac{\text{cm^3}}{\text{min}}$ and $r=20 \text{cm}$ .

We want to find $r'$ .

Let's plug in first:

$25=\frac{4}{3}\pi \cdot 3(20)^2r'$

$25=\frac{4}{3} \pi \cdot 3(400)r'$

$25=\frac{4}{3} \pi \cdot 1200r'$

Multiply both sides by 3:

$75=4 \pi \cdot 1200r'$

$75=4800 \pi r'$

Divide both sides by $4800 \pi$ :

$\frac{75}{4800 \pi}=r'$

$\frac{1}{64 \pi}=r'$

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

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3 years ago

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