Answer:
Step-by-step explanation:
Given
Total = 900
Singing = 600
Dancing = 500
None = 125
Required
Determine the number of students that participate in both
Representing; Singing with S, Dancing with D, Both singing and dancing with B and None with N;
In Set Notation;
Substitute 900 for Total, 600 for S, 500 for D and 125 for N
Open Brackets
Collect Like Terms
Collect Like Terms
Multiply both sides by -1
Reorder
<em>Hence, the number of students that do not participate in both is 325</em>
14.35 is Ur answer to Ur Division
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
number 9 =al you have to do is one and 7 eighths =9 so your sum will be 10 and 7 eighths.
hope this helps;)
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