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Lady_Fox [76]
3 years ago
12

What is the value of

ula"> if p(2) = -24 ?
p(x)=ax^3



________

a = ___? ⟵ question

________
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
p(x) \: = \: a {x}^{3}
p(2) \: = \: a( {2})^{3} \: = \: 24
a \: = \: \frac{24}{8}
a = 3.
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If there are 13 people in club a and 20 people in club b and 25 students in total, how many people are in both clubs?
Svetradugi [14.3K]

Answer:

2 students are in both clubs

Step-by-step explanation:

x = 1 student (this number may be more than the total because one student can be in 2 clubs)

Club a = 13

Club b = 20

13 + 20 = 27x

Total members of clubs - total number of students = 27x - 25 = 2

2 students are in both clubs

Hope this was useful to you!

8 0
3 years ago
What is the area of a rectangle with vertices with (2,3), (7,3), (7,10), and (2,10)
Harlamova29_29 [7]

Answer:

35 square units

Step-by-step explanation:

multiply the base by the hight

5 0
3 years ago
Read 2 more answers
Find the slope of the line passing through the points (-4, -3) and (8, -9).
lana [24]

Answer:

-1/2

Step-by-step explanation:

-9--3=-6

8--4= 12

-6/12

-1/2

5 0
3 years ago
Read 2 more answers
Doug and inc can deliver 52 papers in 44 hours. how long would it take them to deliver 150 ​papers? round to the nearest tenth o
postnew [5]
It would take them about 129.9 hours to deliver all of the paper, because if you divide 44 by 52 you get 0.846153... now multiply that by 150 and you get 129.9230... Now round that to the nearest tenth which is 129.9.

Hope this helps :-)

4 0
4 years ago
The mean June midday temperature in Desertville is 36°C and the standard deviation is 3°C.Assuming this data is normally distrib
AleksandrR [38]

Answer:

The value is  E(X) = 4 \ days

Step-by-step explanation:

From the question we are told that

   The mean is  \mu  =  36^oC

    The standard deviation \sigma =  3^oC

Generally the probability that in June , the midday  temperature is between  

39°C and 42°C is mathematically represented as

      P(39 <  X <  42) = P(\frac{39 - 36}{3}  < \frac{X - \mu }{\sigma} < (\frac{42 - 36}{3} )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

      P(39 <  X <  42) = P(1  < Z

=>   P(39 <  X <  42) = P(Z   < 2) - P( Z

From the z table  the area under the normal curve to the left corresponding to  1 and  2  is

     P(Z   < 2)  = 0.97725

and

    P(Z   < 1)  = 0.84134

    P(39 <  X <  42) = 0.97725  - 0.84134

=>  P(39 <  X <  42) = 0.13591

Generally number of days in June would you expect the midday temperature to be between 39°C and 42°C

      E(X) =  n  *  P(39 <  X 42 )

Here n is the number of days in June which is  n = 30

       E(X) =  30  *   0.13591

=>    E(X) = 4 \ days

8 0
3 years ago
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