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3 years ago

14

The length of a rectangle is 6 inches longer than it’s width what are the possible widths if the area of the rectangle is at lea

st 667 in.²

1 answer:

stealth61 [152]3 years ago

6 0

Let the width = x

length = x + 6

(x + 6) * x = 667

Simplify

x² + 6 = 667

x² + 6 (-6) = 667 (-6)

x² = 661

√x² = √661

x = √661

x = 25.71 (rounded)

25.71 in. is your width

hope this helps

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2 years ago

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A cone has a diameter of 7.5 ft and a height of 4.25 ft. What is the volume of the cone to the nearest tenth? Use 3.14 for π.

leva [86]

Answer:

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3 years ago

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Evgesh-ka [11]

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so... for the case of 20-6x
"x", the domain, or INPUT
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to check for that, let us make the expression to 0, and see what is "x" then

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now, if "x" is 10/3, let's see $\bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0$

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
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\\\\\\

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