3 years ago

Does (lnk)/(k^3), where as k starts at one and continues on to infinity, converge? ...?

1 answer:

max2010maxim [7]3 years ago

7 0

Yes. The numerator does not increase as fast as the denominator increases, causing the function's value to decrease with every subsequent increase in the value of k. This causes the function to converge at a point.

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3 years ago

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