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antoniya [11.8K]
3 years ago
15

Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/16 and the common ratio is 1/4?

Mathematics
2 answers:
Flauer [41]3 years ago
7 0

Answer:

A

Step-by-step explanation:

E2020

ale4655 [162]3 years ago
3 0
Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number

We are given that a(5)=1/16 and r=1/4 so we can say:

1/16=a(1/4)^(5-1)

1/16=a(1/4)^4

1/16=a/256

256/16=a

16=a

So the initial term is 16 so our formula is:

a(n)=16(1/4)^(n-1)


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If you would like to simplify <span>7 - 3[(n^3 + 8n) / (-n) + 9n^2], you can do this using the following steps:

</span>7 - 3[(n^3 + 8n) / (-n) + 9n^2] = 7 - 3[(-n^2 - 8) + 9n^2] = 7 - 3[-n^2 - 8 + 9n^2] = 7 - 3[ - 8 + 8n^2] = 7 - 3[8<span>n^2 - 8] = 7 - 24n^2 + 24 = - 24n^2 + 31
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The correct result would be <span>- 24n^2 + 31.</span>
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
What is the smallest integer that can be divided by the product of a prime number and 7 while yielding a prime number?
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If I'm reading this correctly it is 28.
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Answer:

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Step-by-step explanation:

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