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3 years ago

10

joshua,steve,antonioare baking pie.joshua has 1/2 cups of flour, steve has 1 3/4 cups of flour ,and Antonio has 1 4/6 cups of fl

our . how may cups of flour do they have all together ?

1 answer:

photoshop1234 [79]3 years ago

7 0

Answer:

They all have 3 cups together.

Step-by-step explanation:

I added 1/2 plus 1 3/4 plus 1 4/6 on a calculator and got 3.91666666667

Basically 3.

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Please answer correctly !!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!

balu736 [363]

Answer: It is Right

Step-by-step explanation:

Nas and Pan together makes a abtuse angle but PAN by itself makes a right triangle

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2 years ago

I need help with my homework its about adding whole numbers

Vinvika [58]

Answer:

1- 60

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3 years ago

The variable Z is directly proportional to X. When X is 12, Z has the value 228. What is the value of Z when X = 18

Kisachek [45]

Here, z = kx

k = z/x
k = 228/12
k = 19

So, when x = 18,
z = 19 * 18
z = 342

In short, Your Answer would be: 342

Hope this helps!

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3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago

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