2 years ago

The product of a number, x, and six is four more than the product of the number and three-eighths.

Mathematics

1 answer:

alexdok [17]2 years ago

6 0

The answer issss 6x=38x . 4

You might be interested in

Jim bought a fishing rod for $42. This price was 70% of the original price. What was the original price?

Dmitry [639]

Answer:

54.6

Step-by-step explanation:

42 = 70%

100% - 70% = .30%

42 x 1.3 = 54.6

5 0

2 years ago

–3m − 6 = –4m<br> find m please

RideAnS [48]

Answer:

m=6

Step-by-step explanation:

-3m+4m=6

m=6

3 0

3 years ago

Read 2 more answers

PLEASE HELP. TAKE AT HOME TEST. if u = LN5 and v = LN2, write LN8/15 in terms of u and v. (8/15 is 8 over 25)

astra-53 [7]

Answer:

$\ln( \frac{8}{25} ) = 3v - 2u$

Step-by-step explanation:

We have that

$u= \ln(5)$

and

$v = \ln2$

This implies that;

$5 = {e}^{u}$

and

$2 = {e}^{v}$

Now find and expresion for

$\ln( \frac{8}{25} )$

Which is

$\ln( \frac{8}{25} ) = ln(8) - ln(25)$

$\ln( \frac{8}{25} ) = ln( {2}^{3} ) - ln( {5}^{2} )$

$\ln( \frac{8}{25} ) = 3 ln( {2} ) - 2ln(5)$

$\ln( \frac{8}{25} ) = 3v - 2u$

8 0

3 years ago

Which property justifies this statement? If x=3, then x−3=0. Subtraction Property of Equality Division Property of Equality Refl

IgorLugansk [536]

Answer:

Subtraction Property of Equality Division

Hope this helps (Just took the test btw)

7 0

3 years ago

A rectangle has sides of length 8 cm and 3 cm. Find the length of it's diagonals.

slava [35]

Using pythagoras a^2 + b^2 = c^2
8^2 + 3^2 = c^2
64 + 9 = 73
The square root of 73 is 8.54
So the length of the diagonals are 8.54cm

4 0

3 years ago

Read 2 more answers