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MA_775_DIABLO [31]
3 years ago
15

The product of a number, x, and six is four more than the product of the number and three-eighths.

Mathematics
1 answer:
alexdok [17]3 years ago
6 0
The answer issss 6x=38x . 4
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$1,000

Step-by-step explanatin:

$50,000 * .02 =$1,000

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3 years ago
On a board measuring 1x100, each square is numbered from
max2010maxim [7]

Answer:

97

Step-by-step explanation:

Given the following conditions :

board measuring 1x100, each square is numbered from 1 to 100

Three colors are used to paint the squares from left to right in the sequence :

one blue, two reds and three green squares in a repeated pattern.

What is the highest numbered square that is painted blue?

The sequence of painting is repeated after :

(1 + 2 + 3) = 6 successive squares

Since the number of squares = 100

Maximum complete repetition possible :

100 / 6 = 16 remainder 4

Hence 16 * 6 = 96 (the highest complete sequence terminates on the square numbered 96)

On the 97th square, another sequence begins which is a blue and the 100th square is painted the first of the 3 green colors.

Hence, the highest numbered square that is painted blue is 97

5 0
3 years ago
Read 2 more answers
Which pair represents isotope?<br> a.30 32 15 x and i5 34 19 3?
shutvik [7]
30*5=150
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7 0
3 years ago
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
3 years ago
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