13[6^2 divided by( 5^2 - 4^2)+9] A. 169 B. 585 C.181 D. 26

Aida bought a costume box containing 50 costumes for $300. She sold all of the costumes and made a $250 profit. She sold all of

iris [78.8K]

Answer:$11

Step-by-step explanation: 50c - 300= 250

Add 300 to both sides

Divide both sides by 50

6 0

2 years ago

Please help trying to get my grade up

oksian1 [2.3K]

1. C (x+8)^2
2. D y=6^x
3. D t/2.35 ; 2.13 ft.
4. A (7h^2-2h)/2; 672 cm^2
5. A 4.50 h ; $7.88
For one and two you just have to plug in the numbers into the equation to see what works.
Three four and five you have to read the problems and come up with an equation to get your answer. Please comment if you need to see the work!

3 0

3 years ago

6y+x=8 I need help with this problem

gavmur [86]

Alright so you need to put this equation in slope-intercept form. So you flip the x across the = sign and switch the sign to get 6y=-x+8.
Then you need y by itself so you divide everything by 6. Which gets you y=-1/6x+8/6.
Now simplify
y=-1/6x+4/3 or y=-1/6x+.75
(4/3 =.75)

4 0

3 years ago

.In the Star Wars franchise, Yoda stands at only 66 centimeters tall. Suppose you want to see whether or not hobbits from the Lo

r-ruslan [8.4K]

Answer:

We conclude that the average height of hobbit is taller than Yoda.

Step-by-step explanation:

We are given that in the Star Wars franchise, Yoda stands at only 66 centimetres tall.

From a sample of 7 hobbits, you ﬁnd their mean height $\bar X$ = 80 cm with standard deviation s = 10.8 cm.

Let $\mu$ = average height of hobbit.

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 66 cm {means that the average height of hobbit is shorter than or equal to Yoda}

Alternate Hypothesis, $H_A$ : $\mu$ > 66 cm {means that the average height of hobbit is taller than Yoda}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean height = 80 cm

s = sample standard deviation = 10.8 cm

n = sample of hobbits = 7

So, test statistics = $\frac{80-66}{\frac{10.8}{\sqrt{7}}}$ ~ $t_6$

= 3.429

The value of t test statistics is 3.429.

Now, at 0.01 significance level the t table gives critical value of 3.143 for right-tailed test. Since our test statistics is more than the critical value of t as 3.429 > 3.143, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the average height of hobbit is taller than Yoda.

3 0

4 years ago

Solution to the equation y= -2/3x + 9

NISA [10]

Answer:

I think that we cannot find either x or y

Step-by-step explanation:

Because we need at least two equations

4 0

3 years ago