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Anuta_ua [19.1K]
3 years ago
8

Describe a real-world situation that could be modeled by dividing two rational numbers.

Mathematics
1 answer:
34kurt3 years ago
7 0

Answer:

Dave got the entire office a loaf of bread and it has 11 slices. There where 4 other people that got the bread including dave how many slices would each person get?

Step-by-step explanation:

just divide 11 by 4

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Which choice is equivalent to the expression below?
eimsori [14]

Answer:

C

Step-by-step explanation:

We have the expression:

\sqrt{-100}

Rewriting this yields:

=\sqrt{-1\cdot100}=\sqrt{-1}\cdot\sqrt{100}=i\sqrt{100}=10i

Therefore, our answer is C.

6 0
3 years ago
 10  points for this                                                                                                            
kow [346]
<span>The range would be all real numbers such that 0 ≤ y ≤ 40.

hope this helps!</span>
3 0
4 years ago
Read 2 more answers
Help I’m stuck on this question I’ve been stuck on it for a while I can’t seem to figure it out please help for ten points
Naddika [18.5K]

Answer:

\frac{1}{25}

Step-by-step explanation:

I think what it is trying to say is that it wants the solution to multiplying all of those. The (...) simply means that it wants you to continue that pattern in what you are supposed to be multiplying, but stop at \frac{24}{25}.

That would mean you are technically supposed to be multiplying:

\frac{1}{2}  \frac{2}{3} \frac{3}{4} \frac{4}{5} \frac{5}{6} \frac{6}{7} \frac{7}{8} \frac{8}{9} \frac{9}{10} \frac{10}{11} \frac{11}{12} \frac{12}{13} \frac{13}{14} \frac{14}{15} \frac{15}{16} \frac{16}{17} \frac{17}{18} \frac{18}{19} \frac{19}{20} \frac{20}{21} \frac{21}{22} \frac{22}{23} \frac{23}{24} \frac{24}{25}

That is a lot and unfortunately, none of the individual fractions can be simplified within that. The final answer would be able to be simplified, though.

Multiplying the first four shown: \frac{1}{2}\frac{2}{3} \frac{3}{4} \frac{4}{5} you end up with \frac{24}{120}. Both the numerator (top) and the denominator (bottom) are divisible by 24. Dividing top and bottom would simplify this to \frac{1}{5}.

Now, let's take the next four.

\frac{5}{6}\frac{6}{7} \frac{7}{8} \frac{8}{9} allows you to end up with \frac{1680}{3024}. Both the numerator (top) and the denominator (bottom) are divisible by 336. You are left with \frac{5}{9}.

Now, let's take the next four.

\frac{9}{10}\frac{10}{11} \frac{11}{12} \frac{12}{13}. Multiplying these gives you \frac{11880}{17160}. Both the numerator (top) and the denominator (bottom) are divisible by 1320. You are left with \frac{9}{13}.

Now, let's take the next four.

\frac{13}{14}\frac{14}{15} \frac{15}{16} \frac{16}{17}. Multiplying these gives you \frac{43680}{57120}. Both the numerator (top) and the denominator (bottom) are divisible by 3360. You are left with \frac{13}{17}.

*<em> Although I would continue to say let's take the next four, there appears to be a pattern in the simplification. The numerators we have gotten have all been four less than their denominators, and each numerator has been four more than the last. I cannot be certain, but we only have two sets of four left. If this pattern continues, the simplifications of each should be \frac{17}{21} and \frac{21}{25}. I will continue on for argument's sake, anyways.</em>

The next four are \frac{17}{18}\frac{18}{19} \frac{19}{20} \frac{20}{21}. Multiplying these, you are left with \frac{116280}{143640}. Both the numerator (top) and the denominator (bottom) are divisible by 6840. We are left with\frac{17}{21}. This is the exact guess I had made when following the pattern, and so the next one is most likely going to be the other guess as well.

Our final answer will be \frac{1}{5}\frac{5}{9} \frac{9}{13} \frac{13}{17}\frac{17}{21} \frac{21}{25} all multiplied together. We end up with \frac{208845}{5221125}. Both the numerator (top) and denominator (bottom) are divisible by 208845.

Simplified, your final answer is:  \frac{1}{25}.

* <u>NOTE:</u> that another way to solve this would just be to multiply all numbers from 1-24 together and then 2-25, but you would end up with a very large number that would be just as time consuming to simplify. To get the GCF fast, I used a GCF calculator.

6 0
3 years ago
Assume that two chords in a given circle are the same distance from the
Alenkinab [10]

Step-by-step explanation:

If the two chords are congruent, then they must be equidistant from the centre of the circle.

Answer: <u><em>D) They must be perpendicular</em></u>

A is rejected because the chord might not pass through the center of the circle.

B is rejected because the chords are not obligated to be parallel.

C is rejected because it is not compulsory for the chords to be perpendicular.

4 0
3 years ago
Read 2 more answers
Dadas las funciones f(x) = x + 3, g(x)= x(cuadrada)+ 5x + 6,r(x) = x+2, s(x) = x(cuadrada) - 3x - 10
Aleksandr [31]
So the answer is D hope this would help you

5 0
3 years ago
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