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3 years ago

A 6-meter pole is supported by guy wires that are anchored to the ground as shown. What is sin D?

2 answers:

7 0

<span>If you are given a 6-meter pole that is supported by guy wires that are anchored to the ground, you can create a relationship with respect to sin theta. sin theta is equal to the 6 meters over the slant line supported by the pole. as shown. </span>

navik [9.2K]3 years ago

7 0

Answer:

the answer is 6/6.71

Step-by-step explanation:

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Help me Please I need it !

evablogger [386]

Answer:

Step-by-step explanation:

Given that,

x = -4

f(x)=x² - 4x +6

so,

f(-4)= (-4)² - 4 . (-4) +6

=16 +16 +6

= 38

4 0

3 years ago

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An Individual Retirement Account (IRA) has $17 comma 000in it, and the owner decides not to add any more money to the account

Umnica [9.8K]

Answer: The owner reaches at Rs. 56438.28 after 30 years.

Step-by-step explanation:

Since we have given that

Sum = Rs. 17000

Rate of compounded daily = 4%

Number of years = 30 years

So, Using "compound interest formula" we get that :

$A=P(1+\dfrac{r}{n})^{nt}\\\\A=17000(1+\dfrac{0.04}{365})^{365\times 30}\\\\A=17000(1.000109589)^{10950}\\\\A=56438.28$

Hence, The owner reaches at Rs. 56438.28 after 30 years.

6 0

3 years ago

2357111317 what is the next number

ArbitrLikvidat [17]

The next number will be 19 since you keep adding 2 each time

7 0

3 years ago

A video rental store has 6,000 movies. One Friday, 3/5 of the movies were rented. How many movies were rented that Friday night?

AleksAgata [21]

6000/ 5 = 1200 x 3 =3600 movies

8 0

3 years ago

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The distance between city A and B is 600 km. The first train left A and headed towards B at the speed of 60 km/hour. The secon

hoa [83]

$\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
A&d&60&t\\
B&600-d&v&t+3
\end{array}$

$\bf \textit{meaning}\implies 
\begin{cases}
d=(60)(t)
\\ \quad \\
600-d=(v)(t+3)\\
------------\\
d=\boxed{60t}\qquad thus
\\ \quad \\
600-\boxed{60t}=v(t+3)\leftarrow \textit{solve for "t"}
\end{cases}$

keep in mind, that "t" is the time when the train at A station, left towards B station

they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference

8 0

2 years ago