Lines are perpendicular if the slope of one is the negative reciprocal of the other. In this case the slopes are -8/3 and 8/3, so while negative they are not reciprocal. So no, the two lines intersect but are not perpendicular.
Next time, please share the answer choices.
Starting from scratch, it's possible to find the roots:
<span>4x^2=x^3+2x should be rearranged in descending order by powers of x:
x^3 - 4x^2 + 2x = 0. Factoring out x: </span>x(x^2 - 4x + 2) = 0
Clearly, one root is 0. We must now find the roots of (x^2 - 4x + 2):
Here we could learn a lot by graphing. The graph of y = x^2 - 4x + 2 never touches the x-axis, which tells us that (x^2 - 4x + 2) = 0 has no real roots other than x=0. You could also apply the quadratic formula here; if you do, you'll find that the discriminant is negative, meaning that you have two complex, unequal roots.
4.While not rounding the answer is 500°
Answer:
6v+16
Step-by-step explanation:
2(2v+13) + 2(v-5) > 4v+26+2v-10 > 6v+16
