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mrs_skeptik [129]
3 years ago
15

Could use help on this one! I'll send thanks and mark Brainiest at when finished to see who's correct.

Mathematics
1 answer:
sdas [7]3 years ago
8 0

sqrt (3/10)

sqrt(3)/sqrt(10)

no sqrt in the denominator, so multiply by sqrt(10)/sqrt(1)

sqrt(3) sqrt(10)

-------------------

sqrt(10) sqrt(10)

sqrt(30)/10

Choice D


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Matthew made slightly larger blanket that was 8 Ft long. Its area is 64 sq ft what is its perimeter?
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Answer:

32 ft

Step-by-step explanation:

Given data

Length= 8ft

Area= 64 f^2

Let us find the width

Area= Length*Width

64= 8* Width

Width= 64/8

Width= 8ft

Hence the perimeter= 2L+2W

P= 2*8+2*8

P= 16+16

P= 32 ft

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artcher [175]

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3(x-4)

Step-by-step explanation:

3×4=12 and 3 also goes into 3x

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3(x+3)=30 i have literally forgotten everything about algebra
zhannawk [14.2K]

3(x+3)=30

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What is the minimum of the sinusoidal function? <br><br><br><br>Enter your answer in the box.
kozerog [31]

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Step-by-step explanation:

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7 0
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What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
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