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Gnoma [55]
3 years ago
10

PLEASE HELP MEEE WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
just olya [345]3 years ago
3 0

                                                           Part A)

Given

  • Slope m = 6
  • Point (7, 2)

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

  • m = 6
  • (x₁, y₁) = (7, 2)

substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - 2 = 6(x-7)

Therefore, the equation in​ point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:

y - 2 = 6(x-7)

                                                        Part B)

Given

  • Slope m = -3
  • Point (3, 8)

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

  • m = -3
  • (x₁, y₁) = (3, 8)

substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - 8 = -3(x-3)

Therefore, the equation in​ point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:

y - 8 = -3(x-3)        

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3 0
2 years ago
How do you make this equation 13+5y=6x into slope-intercept form?
Reil [10]
In slope-intercept form, the y variable is isolated.
so,
<span>13+5y=6x
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5y=6x-13
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5 0
3 years ago
What is 10.8 + ( 4.73)
adoni [48]
Hello,

Shall we begin?

    10.80
+    4.73
-----------
    15.53

<span>Answers: 15.53</span>
3 0
3 years ago
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
A rectangle has an area of 96 in2. The rectangle's base is 4 in. What is the height of the rectangle?
gavmur [86]
96/4=24in, so B
Hope this helps :)
6 0
3 years ago
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