Question

PLEASE HELP MEEE WILL GIVE BRAINLIEST!!!!

Answer 1

                                                           Part A)

Given

• Slope m = 6

• Point (7, 2)

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

• m = 6

• (x₁, y₁) = (7, 2)

substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - 2 = 6(x-7)$

Therefore, the equation in​ point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:

$y - 2 = 6(x-7)$

                                                        Part B)

Given

• Slope m = -3

• Point (3, 8)

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

• m = -3

• (x₁, y₁) = (3, 8)

substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - 8 = -3(x-3)$

Therefore, the equation in​ point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:

$y - 8 = -3(x-3)$