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fiasKO [112]
4 years ago
15

What are these values? 1-3) = -1) = f(3) =(

Mathematics
1 answer:
o-na [289]4 years ago
6 0
1-3=-2
-1=-1
I don’t really understand the question but I think no.1 is correct
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2a ⁵ + 5 but a = 5<br> step by step please:D
Sav [38]

Answer:

Step-by-step explanation:

Alright so we are going to be Evaluating on this Equation

So We Substitute for A=5

2a⁵+5

2(5⁵)+5

Step 2

2(5⁵)+5 Simplify

2(3125)+5

6250+5

6255

Your answer would be 6255

5 0
3 years ago
Hello! :)
Free_Kalibri [48]

Answer:okay I’m pretty smart it is c the answer  is 4:)

Step-by-step explanation:

7 0
3 years ago
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Find the greatest common factor pf 110,40,and 120
Ymorist [56]

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5

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6 0
3 years ago
The function g is defined by g(x) = 3x - 5.<br> Find g (2x).
Lady bird [3.3K]
We want to replace x with 2x in the original equation
g(2x) = 3(2x) -5
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5 0
3 years ago
You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu
stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}

C=3\pi r^{2}+ \frac{162 \pi}{r}

We differentiate C with respect to r

C'=6\pi r -\frac{162 \pi}{r^2}

At the minimum cost, C'=0.

Next we solve C'=0 for r

6\pi r -\frac{162 \pi}{r^2}=0

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0
4 years ago
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