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finlep [7]
3 years ago
15

Identify the graphed linear equation. A) y = 1/4 x + 5 B) y = 1/4 x - 5 C) y = 1/4 x + 5 2 D) y = 1/4 x - 5 2

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0

Answer:

The answer Is B) y=1/4 x -5c)

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What is the value of m in 3(2m-9+6m)=3m+29-7m<br> i got 1/10 but the choices are -3, 2, 5, and 120
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Hello,

3(2m-9+6m)=3m+29-7m
==>3(8m-9)=-4m+29
==>24m+4m=29+27
==>28m=56
==>m=2

Answer B


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A (0,0)

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y - 3x < 1

0 - 3(0) < 1

0 < 1

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Which of the following is the quotient of b and a?
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\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby &#10;\begin{array}{llll}&#10;\textit{same base, thus}\\&#10;\textit{exponents must be the same}&#10;\end{array}&#10;\\\\\\&#10;\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}
5 0
3 years ago
If (x+yi)(1-3i)=10 <br> Then x+y=
Naily [24]

Answer:

x + y = 4

Step-by-step explanation:

Given that, (x + iy)(1 - 3i) = 10, then we have to calculate x + y.

Now, (x + iy)(1 - 3i) = 10

⇒ x(1 - 3i) + iy(1 - 3i) = 10

⇒ x - 3xi + iy - 3yi² = 10

⇒ (x + 3y) + i(y - 3x) = 10

Now, comparing the real and imaginary part of both sides we get,

(x + 3y) = 10 ............. (1) and

y - 3x = 0

⇒ y = 3x ............... (2)

Solving equations (1) and (2) we get

x + 3(3x) = 10

⇒ x = 1

So, y = 3x = 3

Therefore, x + y = 1 + 3 = 4 (Answer)

7 0
3 years ago
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