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3 years ago

What is the sum of the geometric sequence 1,3,9... if there were 11 terms?

Mathematics

1 answer:

Delicious77 [7]3 years ago

3 0

Answer:

88,573

Step-by-step explanation:

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What is the answer for -31 = 9+ 8x? Step by Step.

ryzh [129]

Answer:

Step-by-step explanation:

-31=9+8x

we need to isolate the variable by moving 8x to the left side and -31 to the right side....therefore 8x becomes a negative, -8x, and -31 a positive....so now it would look like...

-8x=9+31

then we work the right side out...

-8x=40

to get x we need to divide -8x by 8 so we do the same to the right side as well....

-8x=40

÷8 ÷8

so...

hope this helped you- have a good day bro cya)

4 0

3 years ago

Is algebra.

Reptile [31]

Answer:

(x+9)(x+10)

Step-by-step explanation:

9*10=90

9+10=19

5 0

3 years ago

Read 2 more answers

Find the length of the side of a square with an area of 25

Alexxx [7]

Area squares is the side*side, or
$x^{2} =25$
$\sqrt{ x^{2} } = \sqrt{25}$
$x=5$

So, each side equals 5.

4 0

3 years ago

A particle moves along line segments from the origin to the points (2, 0, 0), (2, 4, 1), (0, 4, 1), and back to the origin under

Shkiper50 [21]

The work is equal to the line integral of $\vec F$ over each line segment.

Parameterize the paths

from (0, 0, 0) to (2, 0, 0) by $\vec r_1(t)=t\,\vec\imath$ with $0\le t\le2$ ,
from (2, 0, 0) to (2, 4, 1) by $\vec r_2(t)=2\,\vec\imath+4t\,\vec\jmath+t\,\vec k$ with $0\le t\le1$ ,
from (2, 4, 1) to (0, 4, 1) by $\vec r_3(t)=(2-t)\,\vec\imath+4\,\vec\jmath+\vec k$ with $0\le t\le2$ , and
from (0, 4, 1) to (0, 0, 0) by $\vec r_4(t)=(4-4t)\,\vec\jmath+(1-t)\,\vec k$ with $0\le t\le1$

The work done by $\vec F$ over each segment (call them $C_1,\ldots,C_4$ ) is

$\displaystyle\int_{C_1}\vec F\cdot\mathrm d\vec r_1=\int_0^2\vec0\cdot\vec\imath\,\mathrm dt=0$

$\displaystyle\int_{C_2}\vec F\cdot\mathrm d\vec r_2=\int_0^1(t^2\,\vec\imath+24t\,\vec\jmath+32t^2\,\vec k)\cdot(4\,\vec\jmath+\vec k)\,\mathrm dt=\int_0^1(96t+32t^2)\,\mathrm dt=\frac{176}3$

$\displaystyle\int_{C_3}\vec F\cdot\mathrm d\vec r_3=\int_0^2(\vec\imath+(24-12t)\,\vec\jmath+32\,\vec k)\cdot(-\vec\imath)\,\mathrm dr=-\int_0^2\mathrm dt=-2$

$\displaystyle\int_{C_4}\vec F\cdot\mathrm d\vec r_4=\int_0^1((1-t)^2\,\vec\imath+2(4-4t)^2\,\vec k)\cdot(-4\,\vec\jmath-\vec k)\,\mathrm dt=-2\int_0^1(4-4t)^2\,\mathrm dt=-\frac{32}3$

Then the total work done by $\vec F$ over the particle's path is 46.

8 0

4 years ago

Is y = 4x + x a linear equation

seraphim [82]

Answer:

yes

Step-by-step explanation:

8 0

2 years ago