<span>Scientific NotationDate: 09/16/97 at 00:42:42
From: Aubin
Subject: Scientific notation
How do you do this problem? I don't understand how you're supposed to
get the answer:
5x10 to the 3rd power = 5,000
5x10 to the -3rd power = -5,000
Is this correct?
<span>Date: 11/03/97 at 09:56:46
From: Doctor Pipe
Subject: Re: Scientific notation
Aubin,
The first part of what you wrote is correct; 5x10 to the 3rd power =
5,000. The second part is not correct.
Writing a negative exponent, such as 10^-3 (read that as ten to the
minus third power) is the same as writing 1/(10^3) (read that as one
over ten to the third power). Notice that the exponent is negative
when writing 10^-3 and positive when writing 1/(10^3) - yet the two
numbers are equal.
Remember that any number to the zeroeth power, say 10^0, is equal
to 1. 10^0 = 1; 5^0 = 1; 275^0 = 1.
Remember also that when multiplying two numbers written as
base^exponent, if the base in both numbers is equal then we add
together the exponents: 10^5 x 10^6
= 10^(5+6)
= 10^11.
If we have a number 10^5, what number do we multiply it by to get 1?
Well, 10^5 x 10^(-5)
= 10^(5 + (-5))
= 10^0
= 1.
So if 10^5 x 10^(-5) = 1
then 10^(-5) = 1 / 10^5
So, since 10^3 = 1,000 then 10^(-3) = 1/(10^3) = 1/1,000 = 0.001 .
It follows from this that:
5x10 to the -3rd power = 5 x 10^(-3) = 5 x 0.001 = 0.005 .
The reason for this can be seen by examining what numbers to the right
of the decimal point represent. You know what numbers to the left of
the decimal point represent: the units digit represents the numeral
times 10^0 (any number to the 0th power is 1), the tens digit
represents the numeral times 10^1, the hundreds digit represents the
numeral times 10^2, and so on.
Well, to the right of the decimal point, the tenths digit represents
the numeral times 10^-1, the hundredths digit represents the numeral
times 10^-2, the thousandths digit represents the numeral times 10^-3,
and so on.
It's important to understand exponents because exponents allow us to
extend the range of numbers that we can work with by allowing us to
easily write and work with very large and very small numbers. It's so
much easier to write:
10^23
then to write:
100,000,000,000,000,000,000,000
Or to write:
10^(-23)
instead of:
0.00000000000000000000001</span></span>
Answer:
0.9 , 0.088 , 0.032
Step-by-step explanation:
0.9 --> 1st greatest
0.088 --> 2nd greatest
0.032 --> 3rd greatest
So, 0.9 , 0.088 , 0.032
Answer:
b- 13 weeks
Step-by-step explanation:
She makes $550 a week but spends $200 on merchandise so her total weekly is technically $350 in order to earn profit she has to get more than $4500
divide $4500 by $350 which you will get 12.6 but you round it to 13 meaning it would take her a maximum of 13 weeks to receive profit
Answer: Choice C)
We start at 0 and move 1.4 units to the right. Then we move another 2.3 units to the right to land on 3.7
Notice how 1.4 - (-2.3) = 1.4 + 2.3 = 3.7
Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
