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3 years ago

PLEASE HELP!! THIS IS MY LAST QUESTION PLEASE!! (Answeer all the problems)

Mathematics

2 answers:

forsale [732]3 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

Given a complex number in standard form a ± bi , then

the conjugate is a ∓ bi

That is the real part is unchanged while the sign of the imaginary part changes.

(22)

The conjugate of $\sqrt{7}$ is - $\sqrt{7}$ ( treat the real part as 0 )

(23)

The conjugate of - 6i is + 6i

(24)

The conjugate of - 2 + i is - 2 - i

Olegator [25]3 years ago

4 0

Answer:

49, 1.5i, 0.25 + 0.5i

Step-by-step explanation:

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Megan slept for 7.5 hours. What is this in hours and minutes?

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7 hours and 50 minutes

7.5 is equal to 7 hours and 50 minutes

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How to solve for 1000(x-2)=75000

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3 years ago

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In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full-time coll

ICE Princess25 [194]

Answer:

a) n = 1037.

b) n = 1026.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

(a) Assume that nothing is known about the percentage to be estimated.

We need to find n when M = 0.04.

We dont know the percentage to be estimated, so we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 2.575*0.5$

$(\sqrt{n}) = \frac{2.575*0.5}{0.04}$

$(\sqrt{n})^{2} = (\frac{2.575*0.5}{0.04})^{2}$

$n = 1036.03$

Rounding up

n = 1037.

(b) Assume prior studies have shown that about 55% of full-time students earn bachelor's degrees in four years or less.

$\pi = 0.55$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 2.575\sqrt{\frac{0.55*0.45}{n}}$

$0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}$

$(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}$

$(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}$

$n = 1025.7$

Rounding up

n = 1026.

6 0

3 years ago

Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex

ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

(a) The mean

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

$\mathbf{Total = 73 +88+85+88+99+134+129}$

$\mathbf{Total = 696}$

The number of days is:

$\mathbf{Day = 7}$

So, the mean is:

$\mathbf{Mean =\frac{Total}{Days}}$

$\mathbf{Mean =\frac{696}{7}}$

$\mathbf{Mean =99.4}$

Hence, the mean number of turkey sandwiches sold is 99.4

(b) The median

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

$\mathbf{Median = 88}$

Hence, the median number of turkey sandwiches sold is 88

(c) The mode

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

$\mathbf{Mode = 88}$

Hence, the mode number of turkey sandwiches sold is 88

(d) The range

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

$\mathbf{Range =134 - 73}$

$\mathbf{Range =61}$

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

6 0

3 years ago