Question

The function f(x) = x2 + 10x – 3 written in vertex form is f(x) = (x + 5)2 – 28. What are the coordinates of the vertex?

Answer 1

The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2 + k, (h, k) is the vertex of the equation.

Answer 2

Answer:

The coordinates of the vertex are $(-5,-28)$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

In this problem we have

$f(x)=(x+5)^{2}-28$

$a=1. h=-5,k=-28$

therefore

Is a vertical parabola open upward

The vertex is a minimum

The vertex is the point $(-5,-28)$