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Natalka [10]
3 years ago
8

The function f(x) = x2 + 10x – 3 written in vertex form is f(x) = (x + 5)2 – 28. What are the coordinates of the vertex?

Mathematics
2 answers:
MrRa [10]3 years ago
5 0
The vertex of the quadratic equation is (-5, - 28). In vertex form, y = a(x - h)2<span> + </span><span>k, (h, k) is the vertex of the equation.</span>
dalvyx [7]3 years ago
5 0

Answer:

The coordinates of the vertex are (-5,-28)

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

In this problem we have

f(x)=(x+5)^{2}-28

a=1. h=-5,k=-28

therefore

Is a vertical parabola open upward

The vertex is a minimum

The vertex is the point (-5,-28)


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