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Over [174]
2 years ago
15

A truck has 4 crates of apples each crate has an equal number of apples all together the truck is carrying 1728 apples how many

apples are in three crates
Mathematics
1 answer:
sdas [7]2 years ago
3 0

Answer:

1296 apples.

Step-by-step explanation:  

We have been given that a truck has 4 crates of apples each crate has an equal number of apples all together the truck is carrying 1728 apples.

First of all let us figure out the number apples in one crate by dividing 1728 by 4.

\text{Number of apples in one crate}=\frac{1728}{4}

\text{Number of apples in one crate}=432

Now we will multiply number of apples in one crate by 3 to find the number of apples in 3 crates.

\text{Number of apples in three crates}=432\times 3

\text{Number of apples in three crates}=1296

Therefore, there are 1296 apples in 3 crates.


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3 years ago
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6w-19 + k when<br> w=8 and k = 2
ddd [48]

Answer:

31.

Step-by-step explanation:

1. Write out the problem.

6w-19 + k; w=8 and k=2

2. Figure out the first part of the problem.

So, if w=8 and 6 and w are next to each other, we should multiply 6*8, which is 48. Next, it says to subtract 19. 48-19=29.

3. Find out what the last part of the problem is.

Since the first part of the problem is 29 and k=2, we should add 29+2=31, which is the final answer.

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3 years ago
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3 years ago
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8 There are a combined 33 students who play a spring sport of track or
Rzqust [24]

The number of students that are on the track team are 18.

The number of students that are on the baseball team are 15.

<h3>What are the linear equations that represent the question?</h3>

a + b = 33 equation 1

a - b = 3 equation 2

Where:

  • a = number of students that are on the track team
  • b = number of students that are on the baseball team

<h3>How many students that are on the baseball team?</h3>

Subtract equation 2 from equation 1

2b = 30

Divide both sides by 2

b = 30/2 = 15

<h3>How many students that are on the track team?</h3>

Subtract 15 from 33: 33 - 15 = 18

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8 0
2 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
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