Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
Answer:
28/32 and 26/32
Step-by-step explanation:
A common denominator of 8 and 16 is 32.
7/8 = (7 * 4)/(8 * 4) = 28/32
13/16 = (13 * 2)/(16 * 2) = 26/32
Two equivalent fractions with a common denominator are 28/32 and 26/32.
Step-by-step explanation:
3x+18+2x-5= -2x+-2+10
combining like terms
3x+2x+2x=5-2+10-18
7x=-5
x=-5/7