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3 years ago

Can you help me put them from greatest to least

Mathematics

2 answers:

erik [133]3 years ago

7 0

Answer:

4, 1, 2, 3

Step-by-step explanation:

9 and 3/4 as a decimal is 9.75 and if you add a zero you can compare it to the other numbers which means 9.750 is the greatest

9.5 when given two zeros will give you 9.500 which makes it the second greatest

9 and 3/8 changed to an improper fraction gives you 75/8 and that as a decimal is 9.375

and we already have 9.125 which u can see is less than the rest

kodGreya [7K]3 years ago

5 0

Answer:

$9\frac{3}{4} ,\:\: 9.5 ,\:\: 9\frac{3}{8} ,\:\: 9.125$

Step-by-step explanation:

$9\frac{3}{4} = 9.75\\\\9\frac{3}{8} = 9.375\\\\9.125 =9.125\\\\9.5 =9.5$

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user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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3 years ago

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Step-by-step explanation:

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