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levacccp [35]
2 years ago
9

Express the product shown as a fraction in simplest form -3/7 dot -2/3 please help

Mathematics
1 answer:
attashe74 [19]2 years ago
8 0

The answer is \frac{2}{7}.

Multiple numerators by nums, and denoms by denoms.

\\\frac{-3}{7} · \frac{-2}{3}  = \frac{6}{21}

\frac{6}{21} simplified is \frac{2}{7}

Hope this helped and branluest would be appreciated

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Use the graph to determine the y intercept
mafiozo [28]

Answers:

  • y intercept:  9
  • zeros:  -3, -1, 1, 3

===============================================

Explanation:

The y intercept is where the curve crosses the y axis. The curve appears to do so just below y = 10, so y = 9 seems like a good estimate. I'm basing this off of the answer choices given. The y intercept always occurs when x = 0.

The zeros, aka roots or x intercepts, are where the curve crosses or touches the x axis. This occurs in four locations: x = -3, x = -1, x = 1 and x = 3. The x intercepts always occur when y = 0.

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For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

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3 years ago
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Answer:

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Step-by-step explanation:

-2x - 5 = -3

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divide both sides by -2

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8 0
3 years ago
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Answer:

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Step-by-step explanation:

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