Answer:
Option A ( radius is twice the daimeter )
Step-by-step explanation:
The relationship between radius and daimeter is given as
Radius² = Daimeter ⇒ r² = d
And cricumference can be calculated with radius
As circumference is 2πr
So the 4ft mailbox’s shadow was six feet. That 2ft longer. According to my logic if the tree had a showdown of 36ft we subtract 2ft. The trees actual size is 34ft.
I might be wrong don’t hate me :(
Answer:
Let L be the length of the rectangle and w be the width of the rectangle.
"The lenght of a rectangle is one less than twice the width" means L=2W-1
Using perimeter formula of a rectangle which is P=2(L+W) you have:
P=2(L+W)
130=2(2W-1+W)
Solve equation above to find W
130=2(3W-1)
130=6W-2
130+2=6W
132=6W
W=22
From here you find L=2W-1=2x22-1=43
Only thing left is to find area A=LxW
