Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs
capital A
lower case and upper case v
lower case and upper case o
lower case and upper case i
lower and upper case w
Answer:
-2
Step-by-step explanation:
Answer:
There are no simple factors to this expression. You can however solve for x, giving you:
x = -1 ± √(y + 3)
Step-by-step explanation:
There is no simple pair of factors to this equation, so we'll have to go through the full process. You can see that by observing that there is no pair of rational numbers that add to make 2 and multiply to make -2. We can however solve for x:
Answer:
10
Step-by-step explanation:
20/2=10 smores
