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marishachu [46]
3 years ago
7

____$$$$!!!!!!!?????

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

To solve, you first want to find the total she hiked in the morning. 1.75+2.4=4.15. Then, you want to subtact the total miles she hiked in the morning from the total miles she hiked in total. 6.5-4.15=2.35. The last step is to compare the miles hiked in the morning compared to the miles in the afternoon by finding the difference. 4.15-2.35=1.8, so therefore she hiked 1.8 more miles in the morning than in the afternoon,

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HELP!! PLEASE!! NEED DONE ASAP I WILL GIVE 100 POINTS AND MORE IF YOU CAN GET ALL 3 QUESTIONS DONE!! THANK YOU!! I WILL ALSO MAR
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Answer:

I answered the questions but that formatting is very confusing and discourages anyone for trying to answer.

The last question is confusing. If I got it wrong, tell me. I will try to answer in the comment section then.

Step-by-step explanation:

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73°. Building A is 30 feet away, and building B is 35 feet away. Which building is taller and by approximately how many feet?

$\text{tan}\theta=\frac{h_{A}}{30} \Rightarrow h_{A}=\text{tan}73\º \cdot 30 \Rightarrow h_{A}\approx 98.12 \text{ feet}$

$\text{tan}\theta=\frac{h_{B}}{35} \Rightarrow h_{B}=\text{tan}73\º \cdot 35 \Rightarrow h_{B}\approx 114.47 \text{ feet}$

\text{Difference} \approx 16.35

Building B is around 16.35 feet taller than building A.

A Look at the figure below: an image of a right triangle is shown with an angle labeled y If sin y° = a divided by 6 and tan y° = a divided by b, what is the value of cos y°?

$\text{sin}(y)=\frac{a}{6} $

$\text{tan}(y)=\frac{a}{b} $

a is the opposite side; 6 is the hypotenuse; b is the adjacent side.

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$\text{cos}(y)=\frac{b}{6} $

If sin f° = eight ninths and the measure of segment YW is 24 units, what is the measure of segment YX? triangle XYW in which angle W is a right angle, angle X measure f degrees, and angle Y measures d degrees.

This seems a bit confusing. The angles don't match. We have 90\º+62\º +21\º \approx 173\º

\text{sin}(f)=0.888...

f \approx 62\º

YX is the hypotenuse of the right triangle.

$\text{cos}(21\º)=\frac{24}{YX} $

YX \approx 25.7

Considering f \approx 69\º

$\text{sin}(69\º)\approx\frac{24}{YX} $

YX \approx 25.7

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Step-by-step explanation:

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I'm given that log4=0.602 and log12=1.079
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Use the quotient rule [ \text{log}_a\frac{x}{y}=log_ax-log_ay ] to simplify.

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