Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
If i remember correctly i think you just cross multiply <span />
keeping in mind that a line with a slope of "0" is a horizontal line, Check the picture below.
9514 1404 393
Answer:
see the attachment
Step-by-step explanation:
The x- and y-intercepts are easily found:
<u><em>X-intercept</em></u>
Set y = 0 and divide by the coefficient of x.
-x +0 = 8
x = -8
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<u><em>Y-intercept</em></u>
Set x = 0 and divide by the coefficient of y.
0 -2y = 8
y = -4
__
Now, we have two points on the graph: (-8, 0) and (0, -4). A third point can be one that is halfway between these: (-4, -2). The graph is attached.
The answer should be b¹². You add the exponents of each constant. In the case of the simple b the exponent would be one.